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If the wavelength of the first member of Balmer series of hydrogen spectrum is `6564A^(@)` , the wavelength of second member of Balmer series will be:A. `1215A^(@)`B. `4848A^(@)`C. `6050A^(@)`D. data given is insufficient to calculate the value |
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Answer» Correct Answer - B `1/lambda=RZ^(2)(1/n_(1)^(2)(-1)/n_(2)^(2)) "for Balmer sereis"` `n_(1)=2` and `n_(2)=3,4,5....` |
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