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If the volume of a block os aluminium is decreased be `1%` the pressure (stress) on is surface is increased by (Bulk moduals) of `Al=7.5xx10^(10)Nm^(-2))`A. `7.5xx10^(10)Nm^(-2)`B. `7.5xx10^(8)Nm^(-2)`C. `7.5xx10^(6)Nm^(-2)`D. `7.5xx10^(4)Nm^(-2)` |
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Answer» Correct Answer - B Given, `(DeltaV)/(V)=1%=(1)/(100)` Bulk modulus, `B=(P)/(DeltaV//V)=(PV)/(DeltaV)` or `P=(BDeltaV)/(V)=7.5xx10^(10)xx(1)/(100)` `=7.5xx10^(8)Nm^(-2)` |
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