If the velocity of the electron is 2.19 x 10 6 m/s. Calculate the wave

1.	If the velocity of the electron is 2.19 x 10 6 m/s. Calculate the wavelengthassociated with it. (1)(h = 6.626 x 10 -34 Kg m 2 /s, m = 9.1 x 10 -31 Kg)
Answer» Solution: According to De Broglie's equation → λ = h/MV; where each one stands for λ = Wavelength h = Plank's Constant m = mass v = VELOCITY Note: mv together can be wrote as “p” which stands for term momentum. → λ = (6.626 × 10⁻³⁴)/(9.1 × 10⁻³¹ × 2.19 × 10⁶) → λ = (6.626 × 10⁻³⁴)/(9.1 × 2.19 × 10⁻³¹⁺⁶) → λ = (6.626 × 10⁻³⁴)/(9.1 × 2.19 × 10⁻²⁵) → λ = (6.626 × 10⁻³⁴⁺²⁵)/(9.1 × 2.19) → λ = (6.626 × 10⁻⁹)/(9.1 × 2.19) → λ = 0.33 × 10⁻⁹ → λ = 3.3 × 10⁻¹⁰ m Wavelength of ELECTRON is 3.3 Å

If the velocity of the electron is 2.19 x 10 6 m/s. Calculate the wavelengthassociated with it. (1)(h = 6.626 x 10 -34 Kg m 2 /s, m = 9.1 x 10 -31 Kg)

Answer»

Solution: According to De Broglie's equation

Note: mv together can be wrote as “p” which stands for term momentum.

→ λ = (6.626 × 10⁻³⁴)/(9.1 × 10⁻³¹ × 2.19 × 10⁶)

→ λ = (6.626 × 10⁻³⁴)/(9.1 × 2.19 × 10⁻³¹⁺⁶)

→ λ = (6.626 × 10⁻³⁴)/(9.1 × 2.19 × 10⁻²⁵)

→ λ = (6.626 × 10⁻³⁴⁺²⁵)/(9.1 × 2.19)

→ λ = (6.626 × 10⁻⁹)/(9.1 × 2.19)

→ λ = 0.33 × 10⁻⁹

→ λ = 3.3 × 10⁻¹⁰ m