If the velocity is decreased by half , how is the Kinetic Energy affec

1.	If the velocity is decreased by half , how is the Kinetic Energy affected if the mass is kept the same.
Answer» Answer: Reduces by factor of 4 Explanation: We know that, K.E of object = 1/2 mv² ....(Formula) $k.e(1) = \frac{1}{2} m {v}^{2}$ Now the Velocity is HALVED by KEEPING mass constant ! $k.e(2) = \frac{1}{2} m ({ \frac{v}{2} })^{2}$ Therefore, $k.e(2) = \frac{1}{2} m \frac{ {v}^{2} }{4}$ THUS, K.E(1) / K.E(2) = {v²} / {v²/4} K.E(1) / K.E(2) = 4/1 Thus, K.E(1) = 4 × K.E(2) K.E(2) = K.E(1) / 4 Hence, If Velocity is halved then the Kinetic Energy is reduced by a factor of 4 If you think I was right surely mark it as BRAINLIEST ANSWER

If the velocity is decreased by half , how is the Kinetic Energy affected if the mass is kept the same.

Answer»

Answer:

Reduces by factor of 4

Explanation:

We know that,

K.E of object = 1/2 mv² ....(Formula)

$k.e(1) = \frac{1}{2} m {v}^{2}$

Now the Velocity is HALVED by KEEPING mass constant !

$k.e(2) = \frac{1}{2} m ({ \frac{v}{2} })^{2}$

Therefore,

$k.e(2) = \frac{1}{2} m \frac{ {v}^{2} }{4}$

K.E(1) / K.E(2) = {v²} / {v²/4}

K.E(1) / K.E(2) = 4/1

Thus,

K.E(1) = 4 × K.E(2)

K.E(2) = K.E(1) / 4