1.

If the value of x-y= 7 and xy=9 then the value of 4x^2+4y^2 is?​

Answer»

Answer:

268

Step-by-step explanation:

4(x^2+4y^2)

= 4(x^2+y^2-2xy+2xy) (Add and SUBTRACT 2xy)

= 4[(x-y)^2+2xy] (As x^2+y^2-2xy=(x-y)^2)

= 4[7^2+2(9)] (as x-y=7, xy=9)

= 4(49+18)

= 4(67)

= 268

Hope it helps!!! Please MARK BRAINLIEST!!!


Discussion

No Comment Found

Related InterviewSolutions