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If the value of acceleration due to gravity on the surface of the earth is 9.8 m/s2, find the mean value of density of earth. Given R = 6400 km and G = 6.67 x 10–11 SI unit |
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Answer» ong>Answer: 11th Physics Gravitation Acceleration due to Gravity the value of g at the surfa... PHYSICS avatar Asked on December 26, 2019 by Shaik Sethi the value of g at the surface of the earth is 9.8m/s . then the value of g at the PLACE 480KM above the surface of the earth will be NEARLY? (Radius of the earth is 6400km ) MEDIUM Help best friend Study later ANSWER M= mass of earth R= radius of earth =6400km=6.4×10 6 m g 1
= acceleration due to gravity on the surface of earth =9.8m/s 2
H= height above the surface of earth 480km=0.480×10 6 m g 2
= acceleration due to gravity above the surface of earth=? acceleration due to gravity on the surface is given g 1
= R 2
GM
----------------------------(1) acceleration due to gravity above the surface is given: g 2
= (R+h) 2
GM
------------------(2) g 1
g 2
= R 2
GM
(R+h) 2
GM
g 1
g 2
= (R+h) 2
R 2
9.8 g 2
= ((6.4×10 6 )+(0.480×10 6 )) 2
(6.4×10 6 ) 2
g 2
=8.5m/s 2 . |
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