If the value of ∣∣∣∣∣(a1−b1)2(a1−b2)2(a1−b3)2(a2−b1)2(a2−b2)2(a2−b3)2(a3−b1)2(a3−b2)2(a3−b3)2∣∣∣∣∣ is k⋅(a1−a2)(a2−a3)(a3−a1)(b1−b2)(b2−b3)(b3−b1), then value of k is

If the value of ∣∣∣∣∣(a1−b1)2(a1−b2)2(a1−b3)2(a2−b1)

1.	If the value of ∣∣∣∣∣(a1−b1)2(a1−b2)2(a1−b3)2(a2−b1)2(a2−b2)2(a2−b3)2(a3−b1)2(a3−b2)2(a3−b3)2∣∣∣∣∣ is k⋅(a1−a2)(a2−a3)(a3−a1)(b1−b2)(b2−b3)(b3−b1), then value of k is
Answer» If the value of $∣ ∣∣∣ ∣ \begin{matrix} {(a_{1} - b_{1})}_{1}^{2} & {(a_{1} - b_{2})}_{1}^{2} & {(a_{1} - b_{3})}_{1}^{2} {(a_{2} - b_{1})}_{2}^{2} & {(a_{2} - b_{2})}_{2}^{2} & {(a_{2} - b_{3})}_{2}^{2} {(a_{3} - b_{1})}_{3}^{2} & {(a_{3} - b_{2})}_{3}^{2} & {(a_{3} - b_{3})}_{3}^{2} \end{matrix} ∣ ∣∣∣ ∣$ is $k \cdot (a_{1} - a_{2}) (a_{2} - a_{3}) (a_{3} - a_{1}) (b_{1} - b_{2}) (b_{2} - b_{3}) (b_{3} - b_{1}),$ then value of $k$ is