Saved Bookmarks
| 1. |
If the temperature and pressure of a gas is doubled the mean free path of the gas molecules |
|
Answer» <P>remains same `gamma=(kT)/(sqrt2pid^(2)P` If T and P are double, `gamma=(2kT)/(sqrt2pid^(2)(2P))=(kT)/(sqrt2pid^(2)P)` |
|