If the system of linear equationsx – 2y + kz = 12x + y + z = 23x –

1.	If the system of linear equationsx – 2y + kz = 12x + y + z = 23x – y – kz = 3has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose equation is - (1) 4x – 3y – 4 = 0 (2) 3x – 4y – 4 = 0(3) 3x – 4y – 1 = 0(4) 4x – 3y – 1 = 0
Answer» Correct option (1) 4x – 3y – 4 = 0 Explanation: x – 2y + kz = 1 …. (i) 2x + y + z = 2 … (ii) 3x – y – kz = 3 … (iii) for locus of (x, y) equation (i) + (iii) 4x – 3y = 4 4x – 3y – 4 = 0

If the system of linear equationsx – 2y + kz = 12x + y + z = 23x – y – kz = 3has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose equation is - (1) 4x – 3y – 4 = 0 (2) 3x – 4y – 4 = 0(3) 3x – 4y – 1 = 0(4) 4x – 3y – 1 = 0

Answer»

Correct option (1) 4x – 3y – 4 = 0

Explanation:

x – 2y + kz = 1 …. (i)

2x + y + z = 2 … (ii)

3x – y – kz = 3 … (iii)

for locus of (x, y)

equation (i) + (iii)

4x – 3y = 4

4x – 3y – 4 = 0

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If the system of linear equationsx – 2y + kz = 12x + y + z = 23x – y – kz = 3has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose equation is - (1) 4x – 3y – 4 = 0 (2) 3x – 4y – 4 = 0(3) 3x – 4y – 1 = 0(4) 4x – 3y – 1 = 0

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