1.

If the surface tension of solution of soap in water is 35 dyne/cm, calculate the work done to form an soap bubble of diameter 14 mm with that solution

Answer»

Solution :Surface tension `S=35` dynes `cm^(-1)=0.035Nm^(-1)`
Radius of the bubble `(R )=(14mm)/(2)=7mm`
`=7XX10^(-3)m`
`W=A(S)=8pir^(2)S`
`implies W=8xx(22)/(7)xx49xx10^(-6)xx0.035`
`W=4.312xx10^(-6)J`


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