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If the sum of the zeros of the polynomial x2 - (k + 3)x + (5k - 3) is equal to one fourth of the product of its zeros find the value of k. |
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Answer» Given polynomial is x2 - (k + 3)x + (5k - 3) Given that sum of zeros = \(\frac14\) x product of zeros i.e., \(\frac{-(-(k +3))}{1} = \frac14 \times \frac{5k -3 }{1}\) ⇒ 4k + 12 = 5k - 3 ⇒ k = 12 + 3 = 15 |
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