1.

If the sum of the zeroes of the quadratic polynomial 3x2-kx+6 is 3, then find the value of k.​

Answer»

Answer:

given ONE ROOT of the Equation is 3

3x^2-kx+6=0

3(3)^2-K*3+6=0

3*9-3k+6=0

27-3k+6=0

-3k+33=0

-3k=-33

k=33/3

k=11

The VALUE of k is 11



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