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If the sum of the zeroes of the quadratic polynomial 3x2-kx+6 is 3, then find the value of k. |
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Answer» Answer: given ONE ROOT of the Equation is 3 3x^2-kx+6=0 3(3)^2-K*3+6=0 3*9-3k+6=0 27-3k+6=0 -3k+33=0 -3k=-33 k=33/3 k=11 The VALUE of k is 11 |
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