| 1. |
If the sum of the first n terms of an A.P. is Sn= 4n-n². Find A.P. and nth term |
|
Answer» ong>Step-by-step explanation: We have been given , Sn = 4n -n^2
Just Think The Given Equation Of The Sum Of " n " TERMS Is correct for all the terms in the AP , So If you PUT n=1 You get Sum of 1 terms which is actually the value of FIRST term A1 . It goes like this , Sn = 4n - n^2 = 4(1) - (1)^2 = 4 - 1 = 3
so The First Term Is 3.
Sum Of 2 Terms Is ... S2 = 4(2) - (2)^2 = 4
Sum of first 2 Terms means a1 + a2 , Now you know a1 and S2 , so S2 - a1 = a2 = 4-3= 1
Now the common difference , a2- a1 = d = 1-3 = -2.
Hence The Basic Method Of Doing That was this .
Solving for a10 , an , a3 we get , a3 = -1 ; a10 = -15; an = 5 - 2n ;
That's It !
hope it helps u buddy.. pls mark me as brainliest : ) |
|