1.

If the square of the difference of zeros of the quadratic polynomial f(x) = x^2 + px + 45 is equal to 144 find the value of p.pls ans asapits urgent

Answer»

<P>ANSWER:

D=b^2-4ac

=p

(p)^2-4(1)(45)

p^2-180=144

p^2=144+180

p^2=324

p=

\sqrt{324}

p=18



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