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If the size of the interior angles of a polygon are 2a, 4a, 6a, 6a, 8a & 10a. What would be the largest and smallest interior angle of the polygon, respectively? |
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Answer» Given :- If the size of the interior angles of a polygon are 2a, 4a, 6a, 6a, 8a & 10A. What would be the largest and smallest interior angle of the polygon, respectively ? Answer :- we know that ,
given that,
so, → 2a + 4a + 6a + 6a + 8a + 10a = (6 - 2) * 180° → 36a = 4 * 180° → a = 20 . then,
[ NOTE :- we can find sum of interior angles if all sides are equal , or regular polygon and in that case all interior angles will also be equal .] Learn more :- The diagram shows a WINDOW made up of a large semicircle and a rectangle The large semicircle has 4 identical section... a rectangular park is of dimensions 32/3 m ×58/5 m. TWO cross roads, each of width 2 1/2 m, run at right angles through ... |
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