If the shortest distance between the straight lines 3(x−1)=6(y−2)= – InterviewSolution

1.	If the shortest distance between the straight lines 3(x−1)=6(y−2)=2(z−1) and 4(x−2)=2(y−λ)=(z−3), λ∈R is 1√38, then the integral value of λ is equal to:
Answer» If the shortest distance between the straight lines $3 (x - 1) = 6 (y - 2) = 2 (z - 1)$ and $4 (x - 2) = 2 (y - λ) = (z - 3), λ \in R$ is $\frac{1}{\sqrt{38}},$ then the integral value of $λ$ is equal to:

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