If the shortest distance between the lines x−33=y−8−1=z−31 and x+3−3=y+72=z−64 is p√30 units, then the value of p is

If the shortest distance between the lines x−33=y−8−1=z−31 and

1.	If the shortest distance between the lines x−33=y−8−1=z−31 and x+3−3=y+72=z−64 is p√30 units, then the value of p is
Answer» If the shortest distance between the lines $\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1}$ and $\frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4}$ is $p \sqrt{30}$ units, then the value of $p$ is

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If the shortest distance between the lines x−33=y−8−1=z−31 and x+3−3=y+72=z−64 is p√30 units, then the value of p is

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