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If the required amount of water is 72 kg then how much C6H14 should be burned per hour?(a) 49.14(b) 39.14(c) 39.14(d) 29.14 |
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Answer» Right answer is (a) 49.14 Easiest explanation: 1 mole of C6H14 = 7 moles of H2O. |
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