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If the radius of the Earth shrinks by 2%, mass remaing same, then how would the have of acceleration due to gravity change? |
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Answer» Solution :`g=(Gm^2)/(R^2)` TAKING logarithm `LOG g = log G+2log m-2log R` Differenntiating it `(dg)/(g)=0+0-2(dR)/(R )= -2[(-2)/(100)]` `(dg)/(g)xx100= -2[(-2)/(100)]xx100=4%`. |
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