1.

If the radius of the earth becomes half of its present value but its density remains unchanged then find the weight of body on the surface of earth.

Answer»

Solution :`implies g =(GM_(e))/R_e^2=G/(R_e^2)(4/3piR_e^3rho)=4/3 piR_erho`
Since the RADIUS becomes HALF,
`g. = 4/3 piG((R_e)/2)rho =1/2 (4/3 pi GR_erho)`
`:. g. =g/2 ` soweight becomes half
Weight `W PROP g`
`:. (W.)/W = (g.)/g`
`:. W. = W XX 1/2`
` :. W. = W/2`


Discussion

No Comment Found