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If the radius of the earth becomes half of its present value but its density remains unchanged then find the weight of body on the surface of earth. |
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Answer» Solution :`implies g =(GM_(e))/R_e^2=G/(R_e^2)(4/3piR_e^3rho)=4/3 piR_erho` Since the RADIUS becomes HALF, `g. = 4/3 piG((R_e)/2)rho =1/2 (4/3 pi GR_erho)` `:. g. =g/2 ` soweight becomes half Weight `W PROP g` `:. (W.)/W = (g.)/g` `:. W. = W XX 1/2` ` :. W. = W/2` |
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