1.

If the radius of earth shrinks by 1% & its mass remain same, the acceleration due to gravity on earth 'surface will

Answer»

The acceleration due to gravity g = GM/r2 = 9.8 m/s2
If r reduces by 1%, the new radius becomes r' = 99% of r = 99r/100 = 0.99r
New acceleration due to gravity g' = GM/(0.99r)2
= GM/(0.98r2 )
= 1.04 g = 10.19 m/s2

Increase in acceleration due to gravity = 10.19 − 9.8 m/s2
=  0.39 m/s
Increase in percentage = 0.39 x 100/9.8 = 3. 97%



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