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If the product of two zeroes of the polynomial 3x cube+5x square -7x -27 be 3 then find the third zero. |
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Answer» Given,Let p, q and r are three zeroes of 3x^3 + 5x^2 - 7x - 27 p*q = 3.......(1) We know,Product of three zeroes of polynomial = - d/a Then, p*q*r = - (-27)/3 = 9......(2) Put value of p*q from eq(1) in eq(2)r = 9/3r = 3 Therefore, third zero is 3 |
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