1.

If the product of two numbers is 1083 and their HCF is 19, then find the numbers of such possible pairs is:1. 32. 53. 44. 1

Answer» Correct Answer - Option 4 : 1

Given:

The product of two numbers is 1083 and their HCF is 19

Concept:

The HCF of two or more numbers is the greatest factor that divides each of them exactly.

Calculation:

Let the number be 19a and 19b

The product of the two numbers = 1083

⇒ 19a × 19b = 1083

⇒ a × b = 1083/361

⇒ a × b = 3

Possible pairs is  (1, 3)

∴ The number of such possible pairs is 1.


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