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If the product of two numbers is 1083 and their HCF is 19, then find the numbers of such possible pairs is:1. 32. 53. 44. 1 |
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Answer» Correct Answer - Option 4 : 1 Given: The product of two numbers is 1083 and their HCF is 19 Concept: The HCF of two or more numbers is the greatest factor that divides each of them exactly. Calculation: Let the number be 19a and 19b The product of the two numbers = 1083 ⇒ 19a × 19b = 1083 ⇒ a × b = 1083/361 ⇒ a × b = 3 Possible pairs is (1, 3) ∴ The number of such possible pairs is 1. |
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