1.

If the product of two numbers is 1014 and their HCF is 13, then find the numbers of such possible pairs is:1. 32. 53. 44. 6

Answer» Correct Answer - Option 3 : 4

Given:

The product of two number is 1014 and their HCF is 13

Concept:

The HCF of two or more numbers is the greatest factor that divides each of them exactly.

Calculation:

Let the number be 13a and 13b

The product of the two number = 1014

⇒ 13a × 13b = 1014

⇒ a × b = 1014/169

⇒ a × b = 6

Possible pairs are (1, 6), (6, 1), (2, 3), (3, 2)

The number of such possible pairs is 4.



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