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If the product of two numbers is 1014 and their HCF is 13, then find the numbers of such possible pairs is:1. 32. 53. 44. 6 |
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Answer» Correct Answer - Option 3 : 4 Given: The product of two number is 1014 and their HCF is 13 Concept: The HCF of two or more numbers is the greatest factor that divides each of them exactly. Calculation: Let the number be 13a and 13b The product of the two number = 1014 ⇒ 13a × 13b = 1014 ⇒ a × b = 1014/169 ⇒ a × b = 6 Possible pairs are (1, 6), (6, 1), (2, 3), (3, 2) ∴ The number of such possible pairs is 4. |
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