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If the probability density function is divided into three regions as shown in the figure, the value of a in the figure is(a) 1/3 (b) 2/3 (c) 1/2 (d) 1/4 |
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Answer» (b) 2/3 The area under the Pdf curve must be unity. All three regions are equi -probable, thus area under each region must be 1/3 Area of region 1 = 2a *1/4 2a/4 = 1/3 = 2/3 |
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