If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk.Find the velocity of the particle at t = 3s.

If the position vector of the particle is given by vecr = 3 t^2 hati +

1.	If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk.Find the velocity of the particle at t = 3s.
Answer» Solution :The velocity `vecv = (dvecr)/(dt) = (dx)/(dt) hati + (dy)/(dt) hatj + (dz)/(dt) HATK ` we obtain `vecv (t) = 6t hati + 5 hatj` The velocity has only two components `v_x = 6t` , depending on TIME t and ` v_y = 5` which is INDEPENDENT of time . The velocity at t = 3s is `vecv (3) = 18 hati + 5hatj `