1.

If the polynomials ax3 + 3x2 - 3x and 2x3 - 5x + a when divided by (x - 4) leave the remainder R1 and R2 respectively. Find the value of a in each of the following cases, if(i) R1 = R2 (ii) R1 + R2=0 (iii) 2R1 - R2 = 0.

Answer»

Let, p (x) = ax3 + 3x2 - 3 and q (x) = 2x 3-5x+a be the given polynomials.

Now,

R1 = Remainder when p (x) is divided by (x – 4)

= p (4)

= a (4)3 + 3 (4)2 – 3 [Therefore, p (x) = ax3 + 3x2 - 3]

= 64a + 48 – 3

R1 = 64a + 45

And,

R2 = Remainder when q (x) is divided by (x – 4)

= q (4)

= 2 (4)3 – 5 (4) + a [Therefore, q (x) = 2x3 - 5x + a]

= 128 – 20 + a

R2 = 108 + a

(i) Given condition is,

R1 = R2 

64a + 45 = 108 + a 

63a – 63 = 0 

63a = 63 

a = 1

(ii) Given condition is R1 + R2 = 0

64a + 45 + 108 + a = 0

65a + 153 = 0

65a = -153

a = \(\frac{-153}{65}\)

(iii) Given condition is 2R1 – R2 = 0

2 (64a + 45) – (108 + a) = 0

128a + 90 – 108 – a

127a – 18 = 0

127a = 18

a = \(\frac{18}{127}\)



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