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If the points `(lambda, -lambda)` lies inside the circle `x^2 + y^2 - 4x + 2y -8=0`, then find the range of `lambda`.A. (-1, 4)B. `(-oo, -1)`C. `(4, oo)`D. [-1, 4] |
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Answer» Correct Answer - A Since the point (a, -a) lies inside the circle `x^(2)+y^(2)-4x+2y-8=0`. `:. a^(2)+a^(2)-4a-2a-8 lt 0` `rArr 2a^(2)-6a-8 lt 0` `rArr a^(2)-3a-4 lt0` `rArr (a-4) (a+1) lt0 rArr -1 lt a lt 4 rArr a in (-1, 4)` |
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