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If the point P(x, y) is equidistant from the points A (6, -1) and B(2, 3), then find a relation between x and y. |
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Answer» By hypothesis PA = PB ⇒ PA2 = PB2 ⇒ (x - 6)2 + (y + 1)2 = (x - 2)2 + (y - 3) ⇒ x2 - 12x + 36 + y2 + 2y + 1 = x2 - 4x + 4 + y2 - 6y + 9 ⇒ 8x - 8y = 24 ⇒ x - y = 3 |
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