Saved Bookmarks
| 1. |
If the point (a-5, 2a-9) lies on the graph of the equation 2x+3y+13=0, find the value of a |
|
Answer» Answer: GIVEN point is(a-5,2a-9) so that X=a-5 ,y=2a-9 given EQUATION is 2x+3y+13=0 put value of x and y in given equation 2(a-5)+3(2a-9)+13=0 2a-10+6a-27+13=0 2a+6a-10-27+13=0 8a-37+13=0 8a- 24=0 8a=24 a=24/8 a=3 Step-by-step explanation: hope it helps |
|