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If the point (2k-3,k+2) line on the graph of equation 2x+3y+15=0, find the value of k. |
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Answer» ong>Step-by-step EXPLANATION: Put the value of (2k-3,k+2) in EQ. 2x+3y+15=0 2(2k-3)+3(k-2)+15=0 4k-6+3k-6+15=0 7k=-15+12 7k=-3 k=-3/7 k=-0.42 Plz mask me the BRAINLIEST answer |
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