if the perimeter of a rectangle be 106 unit and the length exceed the

1.	if the perimeter of a rectangle be 106 unit and the length exceed the breadth by 7units, find the area of the rectangle
Answer» Answer: L=30,b=23 Step-by-step EXPLANATION: length be l and breadth be b then 2(l+b)=106 => l+b=53 ----eqn 1 as GIVEN, =>l-b=7 ------eqn 2 adding both eqns 2l=60 l=30 b=23

if the perimeter of a rectangle be 106 unit and the length exceed the breadth by 7units, find the area of the rectangle

Answer»

Answer:

L=30,b=23

Step-by-step EXPLANATION:

length be l and breadth be b

then 2(l+b)=106

=> l+b=53 ----eqn 1

as GIVEN,

=>l-b=7 ------eqn 2

adding both eqns

2l=60

l=30

b=23

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if the perimeter of a rectangle be 106 unit and the length exceed the breadth by 7units, find the area of the rectangle​

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if the perimeter of a rectangle be 106 unit and the length exceed the breadth by 7units, find the area of the rectangle