If the parallel sides of a parallelogram are 2 cm apart & their sum is

1.	If the parallel sides of a parallelogram are 2 cm apart & their sum is 10 cm. Then it's area is
Answer» We know, $\boxed{\bf Area\:of\:a\:parallelogram\:(A)=breadth\:(b)\times height\:(<klux>H</klux>)}$ As per the QUESTION, In ORDER to find the breadth(b), we have to divide the sum by the height. Given, Sum = 10 cm Height (h) = 2 cm So, Breadth (b) = 10/2 ⇒ Breadth = 5 cm Therefore, Area of parallelogram = b × h ⇒ Area = 5 × 2 ⇒ Area = 10 cm² $\huge\boxed{\bf Area\:of\:Parallelogram=10\:cm^2}$

If the parallel sides of a parallelogram are 2 cm apart & their sum is 10 cm. Then it's area is

Answer»

We know,

$\boxed{\bf Area\:of\:a\:parallelogram\:(A)=breadth\:(b)\times height\:(<klux>H</klux>)}$

As per the QUESTION,

In ORDER to find the breadth(b), we have to divide the sum by the height.

Given,

So,

Breadth (b) = 10/2

⇒ Breadth = 5 cm

Therefore,

Area of parallelogram = b × h

⇒ Area = 5 × 2

⇒ Area = 10 cm²

$\huge\boxed{\bf Area\:of\:Parallelogram=10\:cm^2}$