Saved Bookmarks
| 1. |
If the nth term of a sequence is 5+2n,then the sum of first 20 terms and 30 terms are |
|
Answer» ANSWER:S20=520 S30=1080 Step-by-step explanation: Tn=5+2n T1=a=5+2 (1)=5+2=7 T2=5+2 (2)=5+4=9 Common DIFFERENCE =T2-T1=9-7=2 Sn=n/2 (2A+(n-1)d) S20=20/2 (2 (7)+(20-1)2) = 10 (14+19 (2)) =10 (14+38) = 10 (52) =520// S30=30/2 (2 (7)+(30-1)2) = 15 (14+29 (2)) = 15 (14+58) = 15 (72) = 1080// |
|