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If the most probable velocity of methane at a certain temperature is `400 ms^(-1)`, the kinetic energy of one mole of methane at the same temperature in J is:A. 1024B. 2048C. 3072D. 1920

Answer» Correct Answer - D
`v_(rms) = (sqrt3)/(sqrt2) xx v_(mp)`
`sqrt((2E)/(m)) = (sqrt3)/(sqrt2) xx 400`
`sqrt((2E)/(16 xx 10^(-3))) = (sqrt3)/(sqrt2) xx 400`
On solving:
`E = 1920 J mol^(-1)`


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