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If the most probable velocity of methane at a certain temperature is `400 ms^(-1)`, the kinetic energy of one mole of methane at the same temperature in J is:A. 1024B. 2048C. 3072D. 1920 |
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Answer» Correct Answer - D `v_(rms) = (sqrt3)/(sqrt2) xx v_(mp)` `sqrt((2E)/(m)) = (sqrt3)/(sqrt2) xx 400` `sqrt((2E)/(16 xx 10^(-3))) = (sqrt3)/(sqrt2) xx 400` On solving: `E = 1920 J mol^(-1)` |
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