If the minimum possible de-Broglie wavelength of an electron emitted from a photo-cell is 5.477 Å, then the minimum magnitude of potential difference required to stop the photo current in photo cell will be (in volt) :

If the minimum possible de-Broglie wavelength of an electron emitted f

1.	If the minimum possible de-Broglie wavelength of an electron emitted from a photo-cell is 5.477 Å, then the minimum magnitude of potential difference required to stop the photo current in photo cell will be (in volt) :
Answer» 6 5 8 9 Solution :`lambda_("MIN")=(H)/(sqrt(2mK_("max")))=(h)/(sqrt(2meV_(s)))""[because K_("max")=eV_(s)]` `lambda_("min")=sqrt((150)/(V_(s))) rArr V_(s)=(150)/(lambda_("min"^(2)))"volt"(Å)^(2)` `V_(s)=(150)/((1.8257)^(2)="45 volt"`

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If the minimum possible de-Broglie wavelength of an electron emitted from a photo-cell is 5.477 Å, then the minimum magnitude of potential difference required to stop the photo current in photo cell will be (in volt) :

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