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If the median AD of a triangle ABC divides the angle ∠BAC in the ratio 1 : 2, then sinB/sinC is equal to(a) 2 cos (A/3)(b) (1/2) sec (A/3)(c) (1/2) sin (A/3)(d) 2 cosec (A/3) |
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Answer» (d) 2 cosec (A/3) Step-by-step EXPLANATION: HOPE it helps you |
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