. If the mean distance of a planet from sun is 4 times the mean distan

1.	. If the mean distance of a planet from sun is 4 times the mean distance of earth from sun, then how many years does that planet take to move once around the sun plz answer fast
Answer» Answer: 8 earth year Explanation: From KEPLER Law of planatery motion, we know that square of TIME period of rotation is propoyional to cube of semi MAJOR axis. T² = ka³ Since mean distance from sun is given instead of semi major axis, we will consider a = radius of PLANET orbit. Let T₁ and T₂ , a₁ and a₂ be time period and radius of orbit of the two planet, then ( T₂/T₁)² = (a₂/a₁)³ or ( T₂/T₁)² = (4a₁/a₁)³ or ( T₂/T₁)² = 4³ = (2²)³= 2⁶ or T₂/T₁ = 2³ = 8 or T₂ = 8*1 earth year = 8 earth year

. If the mean distance of a planet from sun is 4 times the mean distance of earth from sun, then how many years does that planet take to move once around the sun plz answer fast

Answer»

Answer:

8 earth year

Explanation:

From KEPLER Law of planatery motion, we know that square of TIME period of rotation is propoyional to cube of semi MAJOR axis.

T² = ka³

Since mean distance from sun is given instead of semi major axis, we will consider a = radius of PLANET orbit.

Let T₁ and T₂ , a₁ and a₂ be time period and radius of orbit of the two planet, then

( T₂/T₁)² = (a₂/a₁)³

or ( T₂/T₁)² = (4a₁/a₁)³

or ( T₂/T₁)² = 4³ = (2²)³= 2⁶

or T₂/T₁ = 2³ = 8

or T₂ = 8*1 earth year = 8 earth year