If the maximum speed of the photoelectron emitted from a potassium surface (ϕ=2.3 eV) is 106 ms−1. What should be the frequency of the incident radiation? (h=6.63×10−34 Joule-sec and melectron=9×10−31 kg)

If the maximum speed of the photoelectron emitted from a potassium sur

1.	If the maximum speed of the photoelectron emitted from a potassium surface (ϕ=2.3 eV) is 106 ms−1. What should be the frequency of the incident radiation? (h=6.63×10−34 Joule-sec and melectron=9×10−31 kg)
Answer» If the maximum speed of the photoelectron emitted from a potassium surface $(ϕ = 2.3 eV)$ is $10^{6} {ms}^{- 1}$ . What should be the frequency of the incident radiation? $(h = 6.63 \times 10^{- 34} Joule-sec and m_{electron} = 9 \times 10^{- 31} kg)$