1.

If the maximum load voltage of 40 V is to be obtained from the bridge rectifier, the value of rms from the secondary is approximately ………

Answer»

0 V
14.4 V
28.3 V
56.6 V

Solution :28.3 V
rms voltage of output
`(V_(0))_("rms")=(V_(m))/(sqrt(2))`
`=(40)/(sqrt(2))=28.8V ~~28.3V`


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