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If the mass of water in vessel "D" is 500 gm and area of its base is 0.7m2 , find the pressure exerted at the base of the vessel, in SI unit? |
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Answer» 2 N/m²Explanation:MASS of water, m = 500 G = 500÷1000 = 0.5 kgWeight of water, F = mg = 0.5×9.8 NArea of base of VESSEL = 0.7m²Pressure = F/A = (0.5×9.8)÷0.7 = 0.5×4 = 2 N/m² |
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