1.

if the mass of a planet is 8 times the mass of the earth and its radius is twice then the radius of the earth what will be the escape velocity for the planet

Answer»

×8Mp = 6×10²⁴ ×8Mp = 48×10²⁴kgRp = Re × 2Rp =6.4×10^6 ×2Rp =12.8×10^6 mVesc of PLANET = √2Gm/R = √2 × 6.67 ×10^-11 Nm/kg² × 48×10²⁴ KG × 12.8×10^6m = √8,196.096 × 10^19 = 8,196.096 × 10^17 = 8,196.096 × 10¹⁴km/s



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