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If the loss in graviational potential energy to falling the sphere by h height and heat loss to surrounding at constant rate H are also taken to account the energy equation will modify to (A) m_(1) s_(1) (theta_(1)-theta) + (m_(1)gh)/(J) = m_(2) s_(2) (theta - theta_(2)) + m_(3) s_(3) (theta - theta_(2)) - H t (B) m_(1)s_(1) (theta_(1) -theta) - (m_(1)gh)/(J) = m_(2)s_(2)(theta -theta_(2)) + m_(3) s_(3) (theta -theta_(2)) + Ht (C) m_(1)s_(1) (theta_(1) -theta) + (m_(1)gh)/(J) = m_(2) s_(2) (theta - theta_(2)) + m_(3) s_(3) (theta -theta_(2)) + Ht (D) m_(1) s_(1) (theta_(1)-theta)-(m_(1)gh)/(J)=m_(2)s_(2)(theta-theta_(2)) +m_(3)s_(3)(theta-theta_(2))-Ht . |
Answer» Solution :HEAT generated `= m_(1) s_(1) (theta_(1)-THETA) + (m_(1)GH)/(J)`  .
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