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If the lines `x+y=6a n dx+2y=4`are diameters of the circle which passes through the point (2, 6), then findits equation. |
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Answer» Here center will be the point of intersection of the diameter, i.e., `C (8,-2)`. Also, the circle passes through the point P(2,6). Then radius is `CP=10`. Hence, the required equation is `(x-8)^(2)+(y+2)^(2)=10^(2)` or `x^(2)+y^(2)-16x+4y-32=0` |
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