If the lines ax+y+1=0,x+by+1=0, and x+y+c=0(a,b,c being different from – InterviewSolution

1.	If the lines ax+y+1=0,x+by+1=0, and x+y+c=0(a,b,c being different from 1) are concurrent, then 11−a+11−b+11−c is
Answer» If the lines $a x + y + 1 = 0, x + b y + 1 = 0, and x + y + c = 0 (a, b, c being different from 1)$ are concurrent, then $\frac{1}{1 - a} + \frac{1}{1 - b} + \frac{1}{1 - c}$ is

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