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If the line y- V3x +3=0 cuts the curve y2 = x+2 at A and B and point on the line P is (V3,0) then |PA.PB| is |
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Answer» We may write y-√3x+3=0 as y-0/√3/2=x-√3/1/2=r....(1) Substituting x = √3+r/2, y=√3r/2 in y^2=x+2, we get 3r^2/4=r/2+√3+23r^2-2r-(4√3+8) =0AP.AQ=|r1.r2|=(4√3+8)/3=4(√3+2)/3. |
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