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If the line `x+2b y+7=0`is a diameter of the circle `x^2+y^2-6x+2y=0`, then find the value of `b` |
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Answer» Correct Answer - `b=5` Here the center of the circle, (3,-1) , must lie on the line `x+2by+7=0`. Therefore, `3-2b+7=0` or `b=5` |
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