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If the line `x-1=0`is the directrix of the parabola `y^2-k x+8=0`, then one of the values of `k`is`1/8`(b) 8 (c) 4(d) `1/4`A. `1//8`B. 8C. 4D. 43469 |
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Answer» Correct Answer - C The equation of the directrix of this parabola is `x-8/k=-k/4" "["Using:"x=-a]` `rArr" "x=8/k-k/4` But, the equation of the directrix is given as x-1=0 `:." "8/k-k/4=1rArrk^(2)+4k-32=0rArrk=-8, 4.` |
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