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if the line my + x = cm passes through the point of intersection of the lines x – 23 = –4y and 7x = 3y + 6 and parallel to the line 5x – 4y = 6‚then find the value of m and c |
Answer» Answer:m = 5 / 4 C = 37 / 5 Step-by-step explanation:Given : A line line passes through intersection of the two lines. We have given two lines EQUATION. We know it line passes through point it value of x and y satisfy every points. We have : x - 23 = - 4 y Multiply it by 3 - 12 y = 3 x - 69 ... ( i ) 7 x = 3 y + 6 Multiply it by 4 12 y + 24 = 28 x - 12 y = 24 - 28 x .... ( ii ) From ( i ) and ( ii ) 3 x - 69 = 24 - 28 x 31 x = 93 x = 3 Putting x = 3 : x - 23 = - 4 y - 4 y = - 20 y = 5 Now we have intersection point ( 3 , 5 ) Also the line m y + x = c m passes so it will satisfy value x and y. 5 m + 3 = c m .... ( iii ) Also given : 5 x - 4 y = 6 is PASSING parallel to m y + x = c Therefore , slope their will be equal : Slope of the line 5 x - 4 y = 6 Comparing with STANDARD equation : A x + B y + C = 0 Slope of line m = - A / B So Slope of the line 5 x - 4 y - 6 = 0 m = 5 / 4 Putting value of m in : 5 m + 3 = c m 25 / 4 + 3 = 5 / 4 c 25 + 12 / 4 = 5 / 4 c 37 = 5 c c = 37 / 5 Hence the value of m is 5 / 4 and c is 37 / 5 . |
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