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If the length of rod A is 3.25 `pm` 0.01 cm and that of B is 4.19 `pm` 0.01 cm then the rod B is longer than rod A byA. `(0.94 pm 0.00)cm`B. `(0.94 pm 0.01)cm`C. `(0.94 pm 0.02)cm`D. `(0.95 pm 0.005 ) cm` |
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Answer» Correct Answer - C Given , length of rod A, `L_(A) = 3.25 pm0.001` length of rod `B, L_(B) = 4.19 pm 0.01` Then , the rod B is longer than rod A by length `Delta l = L_(B) - L_(A)` `rArr" "Delta = (4.19 pm 0.01) - (3.25 pm 0.01)` `Delta = (0.94 pm 0.02) cm` |
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